Fix SQL Syntax error

This commit is contained in:
johnnyq
2023-11-07 16:52:02 -05:00
parent 5d1c283533
commit 3a61b56c6e
2 changed files with 5 additions and 6 deletions

View File

@@ -73,12 +73,11 @@
<option value="">- Driver -</option> <option value="">- Driver -</option>
<?php <?php
// WIP Need to only show users within the session company $sql_users = mysqli_query($mysqli, "SELECT users.user_id, user_name FROM users
$sql_trips = mysqli_query($mysqli, "SELECT users.user_id, user_name FROM users
LEFT JOIN user_settings on users.user_id = user_settings.user_id LEFT JOIN user_settings on users.user_id = user_settings.user_id
WHERE user_role > 1 AND user_archived_at IS NULL ORDER BY user_name ASC" WHERE user_role > 1 AND user_archived_at IS NULL ORDER BY user_name ASC"
); );
while ($row = mysqli_fetch_array($sql_trips)) { while ($row = mysqli_fetch_array($sql_users)) {
$user_id_select = intval($row['user_id']); $user_id_select = intval($row['user_id']);
$user_name_select = nullable_htmlentities($row['user_name']); $user_name_select = nullable_htmlentities($row['user_name']);
?> ?>

View File

@@ -94,11 +94,11 @@
<option value="">- Driver -</option> <option value="">- Driver -</option>
<?php <?php
$sql = mysqli_query($mysqli, "SELECT users.user_id, user_name FROM users $sql_users = mysqli_query($mysqli, "SELECT users.user_id, user_name FROM users
LEFT JOIN user_settings on users.user_id = user_settings.user_id LEFT JOIN user_settings on users.user_id = user_settings.user_id
WHERE user_role > 1 AND user_archived_at > trip_created_at ORDER BY user_name ASC" WHERE user_role > 1 AND user_archived_at > '$trip_created_at' ORDER BY user_name ASC"
); );
while ($row = mysqli_fetch_array($sql_trips)) { while ($row = mysqli_fetch_array($sql_users)) {
$user_id_select = intval($row['user_id']); $user_id_select = intval($row['user_id']);
$user_name_select = nullable_htmlentities($row['user_name']); $user_name_select = nullable_htmlentities($row['user_name']);
?> ?>