AS1024
/
itflow
mirror of https://github.com/itflow-org/itflow
1
0
Fork 0
Code Issues Packages Projects Releases Wiki Activity

Add All Years Option to Income by Clients Report

This commit is contained in:
johnnyq 2023-06-21 16:03:56 -04:00
parent a67a925868
commit ab67929a22
1 changed files with 15 additions and 7 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

22
report_income_by_client.php
View File

@ -4,7 +4,11 @@ require_once("inc_all_reports.php");
validateAccountantRole();
if (isset($_GET['year'])) {
$year = intval($_GET['year']);
if ($_GET['year'] === 'all') {
$year = 'all';
} else {
$year = intval($_GET['year']);
}
} else {
$year = date('Y');
}
@ -26,6 +30,7 @@ $sql_payment_years = mysqli_query($mysqli, "SELECT DISTINCT YEAR(payment_date) A
<div class="card-body">
<form class="mb-3">
<select onchange="this.form.submit()" class="form-control" name="year">
<option value="all" <?php if ($year == 'all') { ?> selected <?php } ?> >All Years</option>
<?php
while ($row = mysqli_fetch_array($sql_payment_years)) {
@ -39,15 +44,18 @@ $sql_payment_years = mysqli_query($mysqli, "SELECT DISTINCT YEAR(payment_date) A
</form>
<?php
$sql_clients = mysqli_query($mysqli, "SELECT c.client_id, c.client_name, SUM(p.payment_amount) AS amount_paid
$sql_clients = "SELECT c.client_id, c.client_name, SUM(p.payment_amount) AS amount_paid
FROM clients AS c
JOIN invoices AS i ON c.client_id = i.invoice_client_id
JOIN payments AS p ON i.invoice_id = p.payment_invoice_id
WHERE YEAR(p.payment_date) = $year
GROUP BY c.client_id
JOIN payments AS p ON i.invoice_id = p.payment_invoice_id";
if ($year != 'all') {
$sql_clients .= " WHERE YEAR(p.payment_date) = $year";
}
$sql_clients .= " GROUP BY c.client_id
HAVING amount_paid > 599
ORDER BY amount_paid DESC"
);
ORDER BY amount_paid DESC";
$sql_clients = mysqli_query($mysqli, $sql_clients);
?>
<div class="table-responsive-sm">